Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
To find the factor tree for 193, you start by determining the prime factors of 193. Since 193 is a prime number itself, the factor tree for 193 would simply consist of the number 193 at the top, as it cannot be broken down further into smaller prime factors. Therefore, the factor tree for 193 would just be a single branch with 193 as the prime factor.
999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.
35 is not divisible by 3.
There is no such number. Since 6 is divisible by 3, then any number that is divisible by 6 automatically has to be divisible by 3.
Yes. 193 is divisible by 1 and 193. It is a prime number.
193 is prime. It is only evenly divisible by itself and one.
Yes, as it is only divisible by one and itself.Yes 193 is a prime number because it has only two factors which are itself and one193 is prime.
There are 193 numbers in between 1 and 250 that are divisible by 2, 3, 5, or 7. Note that if you are not including 250 (so if you meant 1 - 249), then there are 192.
The factors of 772 are: 1, 2, 4, 193, 386, 772
1 and 193. (193 is a prime number)
1 and 193, as it is a prime number.1 and 193
193 is a prime number. Its only factors are 1 and 193.
1 and 193
193 of them are divisible by one (or more) of the given numbers.
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
It is itself because 193 is a prime number