To find the number of integers between 400 and 800 that are divisible by 13, we first need to find the smallest and largest multiples of 13 within this range. The smallest multiple of 13 greater than or equal to 400 is 403, and the largest multiple less than or equal to 800 is 793. To find the count of numbers divisible by 13 in this range, we calculate (793-403)/13 + 1 = 31. Therefore, there are 31 numbers between 400 and 800 that are divisible by 13.
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.
35 is not divisible by 3.
If a number is not divisible by 3 then it is not divisible by 9.
403 is divisible by 1, 13, 31 and 403.
No (not if you want a whole number as an answer).
No: 403 divided by 6 is 67.17
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
To find the number of integers between 400 and 800 that are divisible by 13, we first need to find the smallest and largest multiples of 13 within this range. The smallest multiple of 13 greater than or equal to 400 is 403, and the largest multiple less than or equal to 800 is 793. To find the count of numbers divisible by 13 in this range, we calculate (793-403)/13 + 1 = 31. Therefore, there are 31 numbers between 400 and 800 that are divisible by 13.
Yes - 2418/6 = 403
Other than 1, these two numbers have no other factors in common. They are thus said to be co-prime or relatively prime to each other. 403 = 13 x 31 192 = 26 x 3
403 is composite. It can be evenly divided by 13: 403/13 = 31.
403, 806, 1209, 1612 +403 . . .
Any of its factors which are 1, 13, 31 and itself 403
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
.401