36
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
Out of that list, just 3, 5 and 9.
999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.
35 is not divisible by 3.
675 is not a prime number. It is divisible by 3.
No it is divisible by 5 at least 675/5 = 135 so also divisible by 135, and so on ...
675 is divisible by 5 in addition to 1 and itself. It is a composite number.
Add the digits of the number. If the sum is 9 or divisible by 9, the number itself is divisible by 9. Ex: 675 6 + 7+ 5 = 18 1 + 8 = 9 675 is divisible by 9.
Multiples of 675 are divisible by 675. 675 is divisible by 1, 3, 5, 9, 15, 25, 27, 45, 75, 135, 225, 675
675 of them.675 of them.675 of them.675 of them.
No.
No.
135
The prime factors of 675 are 3, 3, 3, 5, and 5, so 675 is divisible by 3 and 5. It is also divisible by the product of any two or more of those factors so, for instance, 675 is divisible by 9, 15, 25, 27, 75, etc.
Yes.
Every number is divisible by any non-zero number.Any element of the set of numbers of the form 225*k where k is an integer is evenly divisible.