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Which number is completely divisible by 7 and by 23456 and gives remainder as 1?
The number would be (7x23456) + 1 = 164193
How do you find the least number divisible by 23456 with remainder 1?
To find the least number divisible by 23456 with a remainder of 1, you need to find the least common multiple (LCM) of 23456 and the number 1 more than it. The LCM of two numbers is the smallest number that is a multiple of both numbers. In this case, you would calculate the LCM of 23456 and 23457. The LCM can be found by multiplying the two numbers and then dividing by their greatest common divisor.
Which number is divided by 23456 give remainder 1 and it is divided by 7 you get remainder 0?
23457 divided by 23456 leaves a remainder of 1, and it is divisible by 7. So that is one of infinitely many possible answers.
What number can divide 23456 with a remainder of 1?
The most obvious answer would be 5, since 23,455 is divisible by 5 (as are all whole numbers that end in 5 or 0).
Is 23456 prime?
23,456 is an even number, and as such is not a prime number.
