1000 is the smallest 4 digit number but of the two factors, it is only divisible by 2. As 999 is obviously divisible by 3 then 999 + 3 = 1002 is also divisible by 3 and, as an even number, is also divisible by 2. The answer is 1002
1002 is the smallest 4 digit number divisible by 3 and 2.
blank = 2 is a possible answer.
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
If a number is divisible by 4, it also means that the same number is divisible by 2. But if the number ends in a 3, it can't be divisible by 2 and, to a further extent, can't be divisible by 4.
Of 2, 3, 4, 5, and 8, the smallest number divisible by 2 is 2.
1000 is the smallest 4 digit number but of the two factors, it is only divisible by 2. As 999 is obviously divisible by 3 then 999 + 3 = 1002 is also divisible by 3 and, as an even number, is also divisible by 2. The answer is 1002
1002 is the smallest 4 digit number divisible by 3 and 2.
the least number divisible by 1, 2, 3, 4 & 6 is 12.
blank = 2 is a possible answer.
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
2463. The trick is that a number is divisible by 3 if and only if the sum of its digits is divisible by 3. 1+3+2+4 = 10 (not divisible by 3), while 2+4+6+3 = 15 (divisible by 3).
The number 44 is divisible by: 2 - 44/2 = 22 4 - 44/4 = 11 The number is not divisible by 3, 5, 6, or 10.
Yes. If a number is evenly divisible by both 3 and 4, it will also be divisible by 6.This is because the prime factor of 3 is [3] -- in other words, 3 is a prime number -- and the prime factors of 4 are [2, 2].Thus, any number that is divisible by 3 and 4 will have as part of its prime factors the set [2, 2, 3]. (The smallest such number is 12, which is 2 x 2 x 3.) Since the prime factors of 6 are [2, 3] -- and [2, 3] is a subset of [2, 2, 3] -- then any such number must also be divisible by 6.Another way to look at it is to note that all numbers which are divisible by both 3 and 4 are also divisible by 12 (which is 3 x 4). Since 12 is divisible by 6, then all multiples of 12 will also be divisible by 6.
3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.