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3*8*5=120, therefore 120 is divisible by 3, 8 and 5.
840 is the smallest number that is divisible by 5 6 7 and 8.
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
hf
If the last 3 digits are divisible by 8, the number is divisible by 8.