The lowest common multiple of 5 and 6 is 30, so ALL MULTIPLES of 30 are divisible by both 5 and 6, namely:
30, 60, 90, 120, 150, 180, 210, 240, 270, 300, 330, 360, 390, 420, 450, 480, 510, 540, 570, 600, 630, 660, 690, 720, 750, 780, 810, 840, 870, 900, 930, 960, 990, 1020, 1050, 1080, 1110, 1140, 1170, 1200, 1230, 1260, 1290, 1320, 1350, 1380, 1410, 1440, 1470, 1500, 1530, 1560, 1590, 1620, 1650, 1680, 1710, 1740, 1770, 1800, 1830, 1860, 1890, 1920, 1950, 1980, 2010, 2040, 2070, 2100, 2130, 2160, 2190, 2220, 2250, 2280, 2310, 2340, 2370, 2400, 2430, 2460, 2490, 2520, 2550, 2580, 2610, 2640, 2670, 2700, 2730, 2760, 2790, 2820, 2850, 2880, 2910, 2940, 2970, 3000, ...
30.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Any number that is divisible by both 2 and 3 is divisible by 6.
The smallest number that is divisible by 5, 6, and 7 is 210.
30.
30, 60, 90...
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
Multiply 6 x 5 6x10 6x15 and so on if you can get it by multiplying by 6 and 5 both then your good
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Any number that is divisible by both 2 and 3 is divisible by 6.
99990
99990
The smallest number that is divisible by 5, 6, and 7 is 210.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
90 (90/6= 15; 90/5= 19)