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In solving the quadratic equation x2 plus 12x - 5 equals 0 what value would complete the square?
x2 + 12x - 5 = 0x2 + 12x - 5 + 5 = 0 + 5x2 + 12x = 5x2 + 12x + (12/2)2 = 5 + (12/2)2x2 + 12x + (6)2 = 5 + 36(x + 6)2 = 41 (square root of both sides)x + 6 = ± √41x + 6 - 6 = -6 ± √41x = -6 ± √41x ≈ -6 + 6.4 = -0.4x ≈ -6 - 6.4 = -12.4
What is the missing constant term in the perfect square that starts with x^2-12x?
14
What is the discriminant of the equation -3x square - 12x plus 7 equals 8?
The equation is equivalent to: -3x2 - 12x - 1 = 0 [you could change signs to get 3x2 + 12x + 1 = 0 but that is not required] The discriminant is (-12)2 - 4*(-3)(-1) = 144 - 12 = 132
What is the solution of 2x2-12x plus 16 equals 0?
2*2 - 12x +16 =0 4 - 12x +16 =0 -12x + 16 +4 =0 -12x + 20 =0 -12x = -20 x = 1.666666667
12x-4y plus 9z plus 2y?
12x-4y+9z+2y =12x-2y+9z
What number must you add to complete the square x2 plus 12x equals 40?
You must add 36 to complete the square on the left hand side.You must add 36 to complete the square on the left hand side.You must add 36 to complete the square on the left hand side.You must add 36 to complete the square on the left hand side.
What number must be added to both sides of the equation to complete the square x2 12x-6?
To complete the square for the expression (x^2 + 12x - 6), we need to focus on the (x^2 + 12x) part. We take half of the coefficient of (x) (which is 12), square it, and add it to both sides. Half of 12 is 6, and squaring it gives us 36. Therefore, we must add 36 to both sides of the equation.
What number must be added to complete the square of x SQUARED plus 12x equals -3?
9
What number must you add to complete the square of x2 plus 12x equals 40?
The constant term - the part without a variable - must be equal to the square of one half the linear term - the number in front of the "x". That is, it must be (12/2)2 = 36.
What number must you add to complete the square x2 12x -5?
I assume you mean,X2 + 12X - 5 = 0X2 + 12X = 5Now, halve the linear term (12), square it and add it to both sidesX2 + 12X + 36 = 5 + 36factor on the left, gather terms on the right(X + 6)2 = 41(X + 6)2 - 41 = 0==============vertex form.... (- 6, - 41)========================--------------vertexAnd that number added is 36
How do you complete the square x squared plus 12x equals 5?
x^2 + 12x = 5 x^2 + 12x + __ = 5 + __ x^2 + 12x + 36 = 5 + 36 (The 36 I got from taking half of 12 and then squaring that number (which is 6).) (x + 6)^2 = 41 x + 6 = (the square root of 41) x = (the square root of 41) - 6. Hope that helped :)
What number is used to complete the square for the equation x squared minus twelve x equal zero?
x2 - 12x + 36 = (x - 6)2
What number must you add to complete the square x2 plus 12x equals 16?
Add? I will show you the process. X^2 + 12X = 16 halve the linear term (12), square it and ADD it to both sides X^2 + 12X + 36 = 16 + 36 factor the right side; gather terms right (X + 6)^2 = 52 (X + 6)^2 - 52 = 0 (-6,-52) vertex of function As you see 36 was added to both sides
How many square feet is 12x 14?
168 square feet
In solving the quadratic equation x2 plus 12x - 5 equals 0 what value would complete the square?
x2 + 12x - 5 = 0x2 + 12x - 5 + 5 = 0 + 5x2 + 12x = 5x2 + 12x + (12/2)2 = 5 + (12/2)2x2 + 12x + (6)2 = 5 + 36(x + 6)2 = 41 (square root of both sides)x + 6 = ± √41x + 6 - 6 = -6 ± √41x = -6 ± √41x ≈ -6 + 6.4 = -0.4x ≈ -6 - 6.4 = -12.4
What number must you add to complete the square of x2 12x equals 9?
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What is the square root of 12x?
2 root 3x
