The equation is equivalent to: -3x2 - 12x - 1 = 0
[you could change signs to get 3x2 + 12x + 1 = 0 but that is not required]
The discriminant is (-12)2 - 4*(-3)(-1) = 144 - 12 = 132
The discriminant is 25.
This quadratic equation has no real roots because its discriminant is less than zero.
The discriminant in the quadratic equation x2 + 11x + 121 = x + 96 is 0.Simplify the equation to the form Ax2 + Bx + C = 0 and you get x2 + 10x + 25 = 0. The discriminant is B2 - 4AC or 100 - (4)(1)(25) or 100 - 100 or 0.Not asked, but answered for completeness - since the discriminant is 0, there is one real solution, namely x = (-10 +/- 00.5) / 2 = -5
The discriminant is b2 - 4ac. In this case, a = 1, b = 7, and c = 2. Just replace and calculate.
No real roots
The discriminant is -167.
The discriminant is 33.
The discriminant is -11.
The discriminant is 0.
It is: 25-4(8*6) = -167
The discriminant is 9.
This quadratic equation has no solutions because the discriminant is less than zero.
It cannot be solved because the discriminant of the quadratic equation is less than zero
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.
The discriminant is -27 and so there are no real roots.
It has no solutions because the discriminant of the quadratic equation is less than zero.
A discriminant is based on the differences between roots of an equation. A linear equation, such as the onle in the question, has only one root and therefore cannot have a discriminant.