79 + 1 78 + 2 77 + 3
76 + 4 75 + 5 74 + 6 73 + 7 72 + 8
(Etc.) I hope you get the picture.
The numbers are 10 and 8
There's only one number that's equal to 80. It's 80.There's a good chance that there could be three numbers whose sum is 80, or threedifferent numbers whose joint product is 80, but the question doesn't ask for those.
Let's denote the two square numbers as x^2 and y^2. The difference between two square numbers can be expressed as (x^2 - y^2), which can be factored into (x + y)(x - y). Since the difference is 80, we have (x + y)(x - y) = 80. The factors of 80 are 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80. By testing out different combinations of these factors, we find that the pair of square numbers that make a difference of 80 is 82^2 and 2^2.
80 + 80 can equal 160
The two numbers that equal 160 are 80 and 80. This is because when you add 80 to 80, you get 160. Another way to represent this mathematically is 80 + 80 = 160.
They can be: 73+7 = 80
80= 5x5x3+5
The numbers are 10 and 8
100 and 80
2 and 40, for example.
The prime numbers (factors) of 80 are: 2 and 5
32 x 5/√4 = 32 x 5/2 = 80
Numbers that are divisible by 80 are itself and any of its other multiples
u culd make 80
Prime numbers between 71 to 80 = 73 and 79 Therefore there are 2 prime numbers between 71 to 80.
Two of the factors of 80 are prime numbers: 2 and 5.
prime numbers between 50 and 80 = 53,59,61,67 ,71,73,79