First you should take out the common factor. After you do that, in this case you have a difference of square, so you can use the formula for a difference of squares.
-3x2+10x-3 -(3x2-10x+3) -(3x-1)(x-3)
I guess that should be 3 times (x squared) minus 48: 3x2 - 48 = 3(x2 - 16) = 3(x + 4)(x - 4)
-6to work it out: remember BIDMASso 3x2=6! then 6-12=-6
If the original is 2x + 3x2 + 6 + 5x3, you should rearrange the terms in order of exponent:5x3 + 3x2 + 2x + 6
You should use parentheses in your equation to reduce ambiguity. As it is, I can't really tell if the equation means (3x2) - 8x +4 = 0, or if it means 3x(2-8)x +4 = 0. Do you see the difference? Operations inside a parenthesis are done first. Otherwise, we don't know what order is required. And the results are very different.
3x2-y=6 3x2-y=6
You can take an x squared out of both of those, leaving x squared times x plus or minus three depending on what your operation is.
While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
3x2-27 is equal to -21.
Yes. (Assuming that -3x2 is the best representation of 3x2 that this browser will allow.)
First you should take out the common factor. After you do that, in this case you have a difference of square, so you can use the formula for a difference of squares.
-3x2+10x-3 -(3x2-10x+3) -(3x-1)(x-3)
I guess that should be 3 times (x squared) minus 48: 3x2 - 48 = 3(x2 - 16) = 3(x + 4)(x - 4)
3x2=6+38=44
the answer is 3x2
3x2-24x-48 is not factorable.