5x + 10x doesn't need factorization as you can just add them up (5x+10x=15x). However, if you really want to, 5x+10x=5x(1+2)=5x(3)=15x
10x + 3 = 15 10x = 15 - 3 10x = 12 x = 1.2
x3 - 3x2 + x - 3 = (x - 3)(x2 + 1)
3X2 + 6X + 9 3(X2 + 2 + 3) -----------------------3 is a common factor of all terms
x3 + ax + 3a + 3x2 = x (x2 + a) + 3 (a + x2) = x (x2 + a) + 3 (x2 + a) = (x2 + a)(x + 3) Checking the work: x3 + ax + 3x2 + 3a or x3 + 3x2 + 3a + ax = x2 (x + 3) + a (3 + x) = x2 (x + 3) + a (x + 3) = (x + 3)(x2 + a)
3x2 + 10x + 3 = (x + 3)(3x + 1).
3x2 + 10x + 3 = (x + 3)(3x + 1).
6 ^ 3 2 answer:3x2
3x2 + 36x + 81 = 3(x2 + 13x + 27)
54 6 x 9 3x2 3x3 Answer: 3to the 3rd power times 2 3^3x2
3x2 + 33x + 54 =3(x2 + 11x + 18) = 3(x + 9)(x + 2)
5x + 10x doesn't need factorization as you can just add them up (5x+10x=15x). However, if you really want to, 5x+10x=5x(1+2)=5x(3)=15x
X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
3x2 + 10x - 8The auxiliary equation is 3x2 + 10x - 24 [because 8*3 = 24] Two factors of -24 which sum to 10 are 12 and -2. So the factorisation of the auxillary is (3x + 12)*(3x - 2) = 3*(x + 4)*(3x - 2) Dividing by the 3 used to create the auxiliary gives the solution as (x + 4)*(3x - 2).
3x2 + 36x + 81 = 3(x2 + 12x + 27) = 3(x + 3)(x + 9), which are its prime factors; or, if you prefer, 3x2 + 36x + 81 = (3x + 9)(x + 9), which is also accurate. You may easily verify these results by multiplying back.
(3x - 30)(x + 8) can also simplify to 3(x - 10)(x + 8)
If you mean: 27x2-90x+27 then divide all terms by 9 which is then 3x2-10x+3 And when factored it is: (3x-1)(x-3)