21 and 5. 21 x 5 = 105. Simple math.
The prime factors of 105 are 5, 3 and 7. So to work out which two numbers have 105 as an LCM, we just have to share these factors between the two numbers, and add in any duplicates we want. For instance: 5x3 = 15 3x7 = 21 So 15 and 21 have a LCM of 105. 7x5 = 35 3x5 = 15 So 35 and 15 have a LCM of 105. And so on.
√105 in radical form is √105. It has no square factors and so cannot be simplified.
210
10 and 11 sqrt 100 =10 sqrt 121 = 11
Call the integer square roots of the specified pair of numbers l and g for lesser and greater respectively. Then, from the problem statement, g2 - l2 = 105. Possible values for l2 are successively 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, .... , and corresponding values for g2 are 106, 109, 114, 121, ... etc. The first of the latter series that is a perfect square number is 121. Therefore, the square numbers are 121 and 16.
4 is the only square number that is a factor of 84. No square number is a factor of 105.
56 and 105
There is no unique pair of numbers that satisfies these requirements. Suppose a and b is such a pair, and sqrt(105) = x then you want a < x < b But a < (a+x)/2 < x < (b+x)/2 < b So that (a+x)/2 and (b+x)/2 are a closer pair. and you can then find a closer pair still - ad infinitum. The question can be answered (sort of) if it asked about "integers" rather than "numbers". 100 < 105 < 121 Taking square roots, this equation implies that 10 < sqrt(105) < 11 so the answer could be 10 and 11. But (and this is the reason for the "sort of") the above equation also implies that -11 < sqrt(105) < -10 giving -11 and -10 as a pair of consecutive integers. So, an unambiguous answer is possible only if the question specifies positive integers.
Suppose x and y are any two co-prime integers. Then 105*x and 105*y will have a GCF of 105.
52.5 x 2 = 105
The second one.
the simple way is: 100+5=105 but there is ALOT of other ways to get 105
1 and 105 are a factor pair of 105 since 1 x 105= 105 3 and 35 are a factor pair of 105 since 3 x 35= 105 5 and 21 are a factor pair of 105 since 5 x 21= 105 7 and 15 are a factor pair of 105 since 7 x 15= 105
The same as the square root of positive 105, multiplied by i (the imaginary unit). So, the answer will be approximately 10.25i. If only real numbers are acceptable, then there is no solution.
21 and 5. 21 x 5 = 105. Simple math.
7 and 15 21 and 35 15 and 35