Any quadrilateral other than a square or kite could have diagonals meeting at 30 degrees.
A square and a rectangle
There are: 0.5*(302-(3*30)) = 405 diagonals
an acute angle - of 30 degrees.
The formula used to find the number of diagonals in a polygon is n(n-3)/2. 30 x 27/2 = 810/2 = 405 diagonals.
The needle should form a 15 to 30 degree angle with the surface of the arm.
Abcd is a cyclic quadrilateral whose diagonals intersect ata point E.If <dbc=70 and <bac=30. Find <bcd further ab=bc, find <ecd
the diagonals of a rhombus measure 16 cm and 30 cm.find its perimeter.
30 degrees.
30 degrees
Yes. The easiest way to do so is draw a line, then have a right angle at each end, and from the resulting lines draw the final line so it does not form two further right angles. Basically you have 360 degrees to work with. you use 180 degrees up for your two right angles. Now you have 180 degrees left over to work with. you can have one angle be acute (say 30 degrees) and one angle be obtuse (say 150 degrees). This gives you your 2 right angle, non rectangle, quadrilateral.
Oh, dude, let me break it down for you. So, we've got this quadrilateral ABCD with all these angles, right? And we need to find angle AEB, where E is the intersection point of AC and BD. Like, just do a little math magic with those angles, and you'll see that angle AEB is 80 degrees. Easy peasy, lemon squeezy!
it has 19 sides (: