Quadrilaterals do not bisect each other. They could in special cases.
In parallelograms (types of quadrilaterals), the diagonals bisect each other.
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A parallelogram a rectangle a square and a rhombus
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
Not necessarily - the diagonals of a rhombus bisect each other (they are perpendicular bisectors of each other), but are not equal.
"Bisect" means to divide a shape into 2 equal parts. One case where 2 intersecting quadrilaterals bisect each other, is when they are both rectangles, twice as long as they are wide. They could intersect to overlap in way that made 3 squares. One of the squares would be in common. This could be done with the rectangles either lined up, or at right angles.This can also work with 2 identical (or mirrored) parallelograms, where the longer sides are exactly twice as long as the short sides. They could overlap at the ends (in 2 ways, depending whether they are identical or mirrored) to have a rhombus in common. Rectangle, rhombus and square are special cases of parallelogram.When putting questions from school into Answers, be sure to use the same wording. Perhaps "bisect" was not the word.2 quadrilaterals that are of different sizes can not bisect each other.Some quadrilaterals have sides which are all of different lengths.Kite shapes are also quadrilaterals.
An isosceles trapezoid, or any trapezoid, does not have diagonals that bisect each other.