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What number divided by 2 has a remainder 1 divided by 3 has a remainder 1 divided by four has a remainder 1 divided by 5 has a remainder 1 divided by 6 has a remainder 1 divided by 7 has a remainder 0?
301, which can be shown as follows: 301/2 = 150 R 1 301/3 = 100 R 1 301/4 = 75 R 1 301/5 = 60 R 1 301/6 = 50 R 1 301/7 = 43 R 0 In terms of mathematical congruence classes, we need only find a number evenly divisible by 2, 3, 4, 5, and 6 (the smallest is the LCD, 60), and add 1 to get 61, which has a remainder of 1 upon division by 2, 3, 4, 5, and 6. To get a number such that division by 7 yields a remainder of 0, simply add 60 to 61 enough times to reach a number evenly divisible by 7; the smallest is 301: 61 + 4*(60) = 301 --- The other numbers that meet the criteria will be those multiples of 7 that are also one more than a multiple of 60, i.e. higher by the LCD of 2,3,4,5,6, and 7, which is 420. The next numbers are 721, 1141, 1561, and 1981.
What is between 61 107 and are multiples of3 6 7?
There are three numbers between 61 and 107 that are multiples of 3, 6 and 7: 63, 84, 105.
What r the multiples of 3?
the multiples of 3 are........0,3,6,9,12,15,18,21,24,27.... and more
What is 1 minus the quotient of r and 7?
1 - r/7 Another way to write the same thing is 7/7-r/7 which is (7-r)/7
What r the first six multiples of 5?
The first 6 multiples of 5 are: 5, 10, 15, 20, 25, and 30.
