octagon
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(35*(35-3))/2 (35*32)/2 1120/2 560 diagonals
The number of diagonals is n(n-1)/2 - n substitute n=35 35(34)/2 - 35 = 560
triangle
There are 275 diagonals in a shape with 25 sides. The formula is n*(n-3)/2
a decahedron a decahedron