Their sum must be 60.
The sum of the first 15 odd numbers is 225.
75
The sum of 15 and -7 is 8.
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
It is 3/5
Their sum is 328.
Their sum must be 60.
The sum of the first 15 odd numbers is 225.
38,000 is 15% of 253,333.33
6134.67
90
stay alive
0.48
Factoring: 25 = 5x5 and 15 = 5x3. So the factors of 25 and 5 and 5, and the factors of 15 are 3 and 5. The greatest common factor therefore is 5.
please answer my question
8.04