The sum of three consecutive integers is -72
The even integers are 22, 24 and 26.
Presumably the sum is -222, as defined by the question!
Since the three integers are consecutive, let them be: m, m+1, and m+2.Then:m + (m+1) + (m+2) = 72m + m + 1 + m + 2 = 3m + 3 = 723(m+1) = 72m+1 = 24m = 23So the three integers are: {23, 24, 25}. Check and they do in fact sum to 72.
If sum were 75 the integers would be 24, 25 and 26, so the next lowest sum would be 23 + 24 + 25 ie 72. The answer is thus 23.
The sum of three consecutive integers is -72
72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.
The even integers are 22, 24 and 26.
Presumably the sum is -222, as defined by the question!
There are none. However, the two odd numbers are 35 and 37.
Since the three integers are consecutive, let them be: m, m+1, and m+2.Then:m + (m+1) + (m+2) = 72m + m + 1 + m + 2 = 3m + 3 = 723(m+1) = 72m+1 = 24m = 23So the three integers are: {23, 24, 25}. Check and they do in fact sum to 72.
The numbers are 23, 24 and 25.
The numbers are -26, -24, and -22. (all negative numbers can be considered odd or even).
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72
The numbers are -21, -19, -17 and -15.
Two consecutive odd integers are 'X' and 'X+2' . X + (X + 2) = 72 2X + 2 = 72 2X = 70 X = 35 X + 2 = 37
If sum were 75 the integers would be 24, 25 and 26, so the next lowest sum would be 23 + 24 + 25 ie 72. The answer is thus 23.