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Q: What three consecutive integers have a sum of 72?

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The sum of three consecutive integers is -72

The even integers are 22, 24 and 26.

Presumably the sum is -222, as defined by the question!

Since the three integers are consecutive, let them be: m, m+1, and m+2.Then:m + (m+1) + (m+2) = 72m + m + 1 + m + 2 = 3m + 3 = 723(m+1) = 72m+1 = 24m = 23So the three integers are: {23, 24, 25}. Check and they do in fact sum to 72.

If sum were 75 the integers would be 24, 25 and 26, so the next lowest sum would be 23 + 24 + 25 ie 72. The answer is thus 23.

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The sum of three consecutive integers is -72

72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.

The even integers are 22, 24 and 26.

Presumably the sum is -222, as defined by the question!

The numbers are 23, 24 and 25.

Since the three integers are consecutive, let them be: m, m+1, and m+2.Then:m + (m+1) + (m+2) = 72m + m + 1 + m + 2 = 3m + 3 = 723(m+1) = 72m+1 = 24m = 23So the three integers are: {23, 24, 25}. Check and they do in fact sum to 72.

The numbers are -26, -24, and -22. (all negative numbers can be considered odd or even).

23+24+25 = 72

Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72

The numbers are -21, -19, -17 and -15.

23, 24 & 25 :)

Two consecutive odd integers are 'X' and 'X+2' . X + (X + 2) = 72 2X + 2 = 72 2X = 70 X = 35 X + 2 = 37

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