0+-2+3 - its that easy
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
The mean times three will be the total of all three numbers. Multiply the mean times three and subtract the sum of the two numbers from that total.
1+1+17
nine, ten and eleven. Three consecutive numbers that total thirty
Let the numbers be 'n' , 'n+1' & 'n+2' Hence adding n + n+1 + n + 2 = 120 3n + 3 = 120 3n = 117 n = 39 Hence n + 1 = 40 n + 2 = 41 So the three consecutive numbers are ;- 39,40,& 41.
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
55
There are no three consecutive numbers with a sum of 170.
if you mean the three numbers immediately following 1, its 2, 3, and 4.if you mean any three numbers after 1, then...its any three number you choose.There are no numbers after 1 if you want to get technical. Unless you say 1.000, then the three numbers after 1 would be 0's. But 1 alone, there are none.
The mean times three will be the total of all three numbers. Multiply the mean times three and subtract the sum of the two numbers from that total.
The numbers are 110, 111 and 112.
Three composite numbers are 1 3 6
If you are using three distinct numbers and want to find the number of different combinations that can be formed, you would consider the combinations of those numbers. For three numbers, the combinations can be represented as C(3, k) for k = 1 to 3. Thus, the total combinations are 3 (for k=1) + 3 (for k=2) + 1 (for k=3), resulting in a total of 7 unique combinations.
44,45,46
1+1+17
55
Add them together, divide that total by three