EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
The mean times three will be the total of all three numbers. Multiply the mean times three and subtract the sum of the two numbers from that total.
nine, ten and eleven. Three consecutive numbers that total thirty
1+1+17
Let the numbers be 'n' , 'n+1' & 'n+2' Hence adding n + n+1 + n + 2 = 120 3n + 3 = 120 3n = 117 n = 39 Hence n + 1 = 40 n + 2 = 41 So the three consecutive numbers are ;- 39,40,& 41.
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
55
There are no three consecutive numbers with a sum of 170.
The mean times three will be the total of all three numbers. Multiply the mean times three and subtract the sum of the two numbers from that total.
if you mean the three numbers immediately following 1, its 2, 3, and 4.if you mean any three numbers after 1, then...its any three number you choose.There are no numbers after 1 if you want to get technical. Unless you say 1.000, then the three numbers after 1 would be 0's. But 1 alone, there are none.
The numbers are 110, 111 and 112.
44,45,46
Add them together, divide that total by three
55
Three composite numbers are 1 3 6
nine, ten and eleven. Three consecutive numbers that total thirty
Sure thing, honey. You can place the numbers 1, 3, and 6 in the first circle, 2, 4, and 7 in the second circle, and 5 in the third circle. Each straight line of three numbers will add up to 10. Easy peasy lemon squeezy!