Let the smaller integer be x, then then larger integer is x + 2, and:
3x + (x + 2) = 58
→ 4x = 56
→ x = 14
→ The two integers are 14 and 16.
Call the unknown higher integer h. Then, from the problem statement, 4h + (h-2) = 98; 5h = 100; h = 20. Thus the two integers are 18 and 20.
Let the two odd numbers be n and n+2, then : 2(n + 2) + 13 = 3n 2n + 4 + 13 = 3n n = 17 The smaller of the two odd numbers is 17 and the larger number is 19.
The representation of an odd integer is 2n + 1. So the other consecutive odd integer will be 2n + 3,[(2n + 1) + 2]. Thus, we have:2(2n + 3) + 13 = 3(2n + 1)4n + 6 + 13 = 6n + 3 subtract 4n and 3 to both sides16 = 2n divide by 2 to both sides8 = n2n + 1 = 2(8) + 1 = 16 + 1 = 172n + 3 = 2(8) + 3 = 16 + 3 = 19Therefore, theses numbers are 17 an 19.Check:3(17) - 2(19) = 13 ?51 - 38 = 13?13 = 13 True
The difference (greater minus lesser) is the distance between them.
Lesser
The integers are the sqare root of 121 and 81 to the 2/4 power.
58 = 3x + yy = x-258 = 3x + x-258 = 4x - 256 = 4x14 = xx-2 = yy = 16Let x= the lesser integer=14Let x+2 = the larger integer=163(x)+(x+2)=583x+x+2=584x+2=584x=56x=14x+2(14)+216Let the smaller number be n, then the larger number is n + 2.3n + (n + 2) = 58 : 4n + 2 = 58 : 4n = 56 : n = 14. then n + 2 = 16The two consecutive even numbers are 14 and 16.
Call the unknown higher integer h. Then, from the problem statement, 4h + (h-2) = 98; 5h = 100; h = 20. Thus the two integers are 18 and 20.
Let the two integers be m-1 & m, so the lesser integer is m-1, and the greater integer is m:(m-1) + 3*m = 43 --> 4*m -1 = 43 --> 4*m = 44, m = 11 & m-1 = 10, so 10 & 11Check: 11 times 3 is 33, add 10 is 43
3(n + 2) = n - 10 3n + 6 = n - 10 2n + 6 = -10 2n = -16 n = -8 -8 and -6
6 and 8
Let the two odd numbers be n and n+2, then : 2(n + 2) + 13 = 3n 2n + 4 + 13 = 3n n = 17 The smaller of the two odd numbers is 17 and the larger number is 19.
Let's denote the unknown integer as "x". So now we have two integers, "x" and "4x" because one integer is 4 times the other. So the sum of x+4x= 5x 5x = 5 So x=1
The two integers you are looking for would be 10 and 12. 12X3=36 therefore 10+(12X3)=46. Voila.
Not exactly. All positive integers are greater than all negative integers, but -1 is greater than -7 even though -7 is farther from zero. It's better to think of a number line. Things get greater as you move to the right, lesser as you move to the left.
To order integers from greatest to least on a number line, first identify the positions of each integer on the line. The integers that are farther to the right represent greater values, while those to the left represent lesser values. Starting from the rightmost integer, you would list the integers in descending order until you reach the leftmost one. This visual representation helps clearly see the relative sizes of the integers and facilitates accurate ordering.
The quotient will be less than one.