Call the unknown higher integer h. Then, from the problem statement, 4h + (h-2) = 98;
5h = 100; h = 20. Thus the two integers are 18 and 20.
Consecutive integers mean the numbers follow one after the other. So, if you let x be an integer, then x, x+1, and x+2 are your three consecutive integers. "Sum" means they were added. So: x+(x+1)+(x+2)=237 => 3x+3 = 237 => 3x = 234 => x=78. Therefore, your integers are: 78, 79, and 80.
10,12
The three numbers added together will equal 228. The average of the three numbers will be 228 / 3 = 76. If you take one even integer from either side of 76, you get 74 and 78.Therefore, the three consecutive even integers which equal 228 are 74, 76 and 78.
6x + 5 = 53 6x = 48 x = 8 8 + 45 = 53 8 and 9
Let the smaller integer be x, then then larger integer is x + 2, and: 3x + (x + 2) = 58 → 4x = 56 → x = 14 → The two integers are 14 and 16.
6 and 8
The two integers you are looking for would be 10 and 12. 12X3=36 therefore 10+(12X3)=46. Voila.
Consecutive integers added or subtracted will turn out to be odd numbers. You can't make 8 with consecutive integers.
Let the two integers be m-1 & m, so the lesser integer is m-1, and the greater integer is m:(m-1) + 3*m = 43 --> 4*m -1 = 43 --> 4*m = 44, m = 11 & m-1 = 10, so 10 & 11Check: 11 times 3 is 33, add 10 is 43
There are no two consecutive even integers that can be added, subtracted, ordivided to get 1,088.But if you multiply 32 by 34, you get 1,088 .
There are no such integers.
12 and 13.
The integers are 10 and 11.
124+125+126=375
55 and 57
44
Consecutive integers mean the numbers follow one after the other. So, if you let x be an integer, then x, x+1, and x+2 are your three consecutive integers. "Sum" means they were added. So: x+(x+1)+(x+2)=237 => 3x+3 = 237 => 3x = 234 => x=78. Therefore, your integers are: 78, 79, and 80.