Let's denote the unknown integer as "x". So now we have two integers, "x" and "4x" because one integer is 4 times the other.
So the sum of x+4x= 5x
5x = 5
So x=1
It is two times the magnitude of the integer.
The other integer is -18 because -5 times -18 = 90
The integers would begin with 10.
The let statement is: let the smallest of the three integers be x.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
That has no integer solution. Three times an integer is another integer; if you subtract to integers, you get an integer again, not a fraction.
8
The smaller integer is 6, the larger integer is 32
If a and b are integers, then a times b is an integer.
The sum of three consecutive integers is -72
Let the two integers be m-1 & m, so the lesser integer is m-1, and the greater integer is m:(m-1) + 3*m = 43 --> 4*m -1 = 43 --> 4*m = 44, m = 11 & m-1 = 10, so 10 & 11Check: 11 times 3 is 33, add 10 is 43
Let the smaller integer be x, then then larger integer is x + 2, and: 3x + (x + 2) = 58 → 4x = 56 → x = 14 → The two integers are 14 and 16.
Call the unknown higher integer h. Then, from the problem statement, 4h + (h-2) = 98; 5h = 100; h = 20. Thus the two integers are 18 and 20.
It is two times the magnitude of the integer.
The integers are 5 and 7.
The other integer is -18 because -5 times -18 = 90
The integers would begin with 10.