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What would 2a x 2 be?

Updated: 4/28/2022
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13y ago

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4a

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Q: What would 2a x 2 be?
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2a x 2a?

The answer is 4a^2.


What is 2a x a?

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What is the area of an equilateral triangle of side 2a?

The height of an equilateral triangle is √3/2 x side_length. So for an equilateral triangle of side length 2a, the area is: area = 1/2 x base x height 1/2 x (2a) x (√3/2 x 2a) = √3 a2


What is the GCF of 4a and 10a monomials?

Factor them. 2 x 2 x a = 4a 2 x 5 x a x a = 10a2 Select the common factors. 2 x a = 2a, the GCF.


What is 2a x 2?

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What is 6ab x 2a x 3 x 2 x 2?

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What is the difference between a x a and 2a?

a x a means that a is multiplied by a. 2a means that a is multiplied by 2. Unless a happens to be 2, a x a will give a different result.The difference is a x (a-2). for example if a = 2, then the difference is zero. If a = 3, the difference is 3The operators are different: 2a = a + a (addition).


How would you factor the polynomial 4A squared minus B squared?

4aa-bb fits the special type of polynomial in the form of x**2-y**2 which can be rewritten as (x-y)(x+y) sqrt(4aa) = 2a sqrt(bb) = b (2a-b)(2a+b)


Where did the quadratic formula come from?

The quadratic formula originated from the concept of completing the square. let's take ax2 + bx + c = 0. To complete the square, solve for x. Subtract c. ax2 + bx = -c. Then divide by a [notice- if there is no a value, then a=1]. x2 + bx/a = -c/a. Add (b/2a)2 to both sides. x2 + bx/a + b2/4a2 = -c/a + b2/4a2 Factor/Reformat. (x + b/2a)2 = (b2-4ac) / 4a2 (x + b/2a)2 = [(b2-4ac) / 2a]2 Square-root both sides. x + b/2a = ± √(b2-4ac) / 2a Subtract b/2a. x = -b/2a ± √(b2-4ac) / 2a Combine terms. x = [-b ± √(b2-4ac)] / 2a


Where did the quadratic equation come from?

The quadratic formula originated from the concept of completing the square. let's take ax2 + bx + c = 0. To complete the square, solve for x. Subtract c. ax2 + bx = -c. Then divide by a [notice- if there is no a value, then a=1]. x2 + bx/a = -c/a. Add (b/2a)2 to both sides. x2 + bx/a + b2/4a2 = -c/a + b2/4a2 Factor/Reformat. (x + b/2a)2 = (b2-4ac) / 4a2 (x + b/2a)2 = [(b2-4ac) / 2a]2 Square-root both sides. x + b/2a = ± √(b2-4ac) / 2a Subtract b/2a. x = -b/2a ± √(b2-4ac) / 2a Combine terms. x = [-b ± √(b2-4ac)] / 2a


Find the value of c for which the roots of 2x2-21x c0?

2x^2 - 21x + c = 0 x^2 - 21x/2 + c/2 = 0 (x + a)(x + 2a)= x^2 - 21x/2 + c/2 x^2 + 3a + 2a^2 3a = -21/2 ------> a = -7/2 2a^2 = c/2 ---> 49/2 = c/2 ---> c = 49