The nth term of a Geometric Series is arn-1.
Then a(4) = 3√2 x (√2)³ = 3(√2)4.........as √2 x √2 = 2 then (√2)4 = 4
Thus, a(4) = 3 x 4 = 12.
the series can be 1,-4,16,-64
Well, honey, if the first term is 7 and the common ratio is 1.1, all you gotta do is multiply 7 by 1.1 three times to find the fourth term. So, 7 x 1.1 x 1.1 x 1.1 equals 9.697. So, darling, the fourth term of this geometric sequence is 9.697.
A geometric sequence is an ordered set of numbers such that (after the first number) the ratio between any number and its predecessor is a constant.
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
11.27357
the series can be 1,-4,16,-64
Well, honey, if the first term is 7 and the common ratio is 1.1, all you gotta do is multiply 7 by 1.1 three times to find the fourth term. So, 7 x 1.1 x 1.1 x 1.1 equals 9.697. So, darling, the fourth term of this geometric sequence is 9.697.
A geometric sequence is an ordered set of numbers such that (after the first number) the ratio between any number and its predecessor is a constant.
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
36
-1,024
11.27357
They are 14, 42, 126, 378 and 1134.
It is 1062882.
A geometric sequence with 5 terms can alternate by having positive and negative terms. For example, one such sequence could be (2, -6, 18, -54, 162). Here, the first term is (2) and the common ratio is (-3), leading to alternating signs while maintaining the geometric property.
The given sequence is a geometric sequence where each term is multiplied by 2 to get the next term. The first term (a) is 4, and the common ratio (r) is 2. The nth term of a geometric sequence can be found using the formula ( a_n = a \cdot r^{(n-1)} ). Therefore, the nth term of this sequence is ( 4 \cdot 2^{(n-1)} ).
A geometric series represents the partial sums of a geometric sequence. The nth term in a geometric series with first term a and common ratio r is:T(n) = a(1 - r^n)/(1 - r)