222222222222
142
You can't have a remainder of 6 when you divide by 2! JHC!
903.75
73.75
3.5
To find the number that gives a quotient of 5 and a remainder of 3 when divided by 7, we can use the formula: ( \text{number} = \text{divisor} \times \text{quotient} + \text{remainder} ). Here, the divisor is 7, the quotient is 5, and the remainder is 3. So, the calculation is ( 7 \times 5 + 3 = 35 + 3 = 38 ). Therefore, the number is 38.
To find the number, you can use the formula: number = (divisor × quotient) + remainder. In this case, the divisor is 43, the quotient is 3, and the remainder is 28. So, the calculation would be: (43 × 3) + 28 = 129 + 28 = 157. Therefore, the number is 157.
607.5
142
488.375
The largest 2-digit number is 99. When 99 is divided by 4, the quotient is 24 with a remainder of 3. This is because 99 divided by 4 equals 24 with a remainder of 3.
387 divided by 6 is 64 with remainder 3.
44.3333
3 divided by 2 gives 1r1
(7 x 4) + 3 = 31
You can't have a remainder of 6 when you divide by 2! JHC!
537 divided by 7 is quotient 76 with remainder 5