A horizontal line has a slope of 0. If you're using the slope formula, then when the numerator is equal to 0 then the slope is 0.
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
Thing is, 3 doesn't equal 0.03... But... using false logic, it could be proved: Do we agree: 0/3 = 0/0.03 = 0 We know if: n/a = n/b then, a =b. Therefore, 3 = 0.03 However, you can't do that with a 0, so 3 doesn't equal 0.03
No; they are not equal.
0 + 0 = 0
Its truth table is: input output 0 1 1 0
Input Output 0 1 1 0
I don't really know what this is supposed to mean, if you want to print the truth-table of the NAND-gate that will be something like this: for (a=0; a<=1; ++a) for (b=0; b<=1; ++b) printf ("%d %d %d\n", a, b, !(a&&b))
. p . . . . . q. 0 . . . . . 1. 1 . . . . . 0
.....0 10 | 0 01 | 0 1.....0 10 | 0 11 | 1 10 | 11 | 0
apparently whenever you can swap the 0's for 1's and 1's for 0's in the truth table and the truth result remains unchanged.
Truth table of 'NAND' is 0 0 - 1 0 1 - 1 1 0 - 1 1 1 - 0 NAND is just opposite of AND as the name itself suggest NAND is the not of AND Truth table of "NOR" is 0 0 - 1 0 1 - 0 1 0 - 0 1 1 - 0 NOR is just opposite of OR as the name itself suggest NOR is the not of OR.
#include<iostream> int main() { std::cout << "Truth table for AND gate\n\n"; std::cout << " |0 1\n"; std::cout << "-+---\n"; for (unsigned a=0; a<2; ++a) { std::cout << a << '|'; for (unsigned b=0; b<2; ++b) { std::cout << (a & b) << ' '; } std::cout << '\n'; } std::cout << std::endl; }
It is the very same in every programming language. For example: AND: 0 && 0 = 0 0 && 1 = 0 1 && 0 = 0 1 && 1 = 1
Because if input A *and* input B is true, then the output is true! Truth table of AND gate: ┌─┬─╥───────┐ │A│B║Q (Output)│ ├─┼─╫───────┤ │0│0║0..............│ ├─┼─╫───────┤ │0│1║0............. │ ├─┼─╫───────┤ │1│0║0............. │ ├─┼─╫───────┤ │1│1║1............. │ └─┴─╨───────┘
A horizontal line has a slope of 0. If you're using the slope formula, then when the numerator is equal to 0 then the slope is 0.
The simplest way to describe this action is to demonstrate using a simple truth table. This is not intended to be an in depth study of the theorms but a simple demonstration of how a trivial equation can be demorganized. Given a simple boolean equation !A+!B=1. One could show in a truth table. !A !B !A+!B (fully inhibited OR function) 0 0 1 0 1 1 1 0 1 1 1 0 Demorganizing (hypersimplified method) 1) NOT all variables 2) NOT the equation 3) Invert the function (AND to OR or OR to AND) Iterative steps yeilds !A becomes !!A which is the same as A (!!A + !B) = (A+!B) !B becomes !!B which is the same as B (A +!!B) = A+B OR function becomes AND (A+B) = (AB) NOT the full equation !(AB) = !A+!B Truth table for the new equation (which happens to be a NAND function) A B AB !AB !A+!B 0 0 0 1 1 0 1 0 1 1 1 0 0 1 1 1 1 1 0 0