The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
Using the distance formula the length of ab is 5 units
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If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
Using the distance formula the length of ab is 5 units
(0,8)2 + (0,2)2 8(2=69 2(2=4 69+4=74√
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8
The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.
We can't see the drawing, so we don't know how QX is related to AB. Maybethat's the whole problem. Perhaps you ought to look at the drawing.
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
l x w =8 (1) l - w = 2 (2) transpose (2) l = 2+w sub into (1) w(2+w)=8 w 2 +2w - 8 = 0 (w+4)(w-2) = 0 w= -4,2 width = 2 feet, length = 2+2 = 4 feet