The answer is 43 and the reason why the tens digit changes is because 7 + anything over 2 will change the digit. If just added 7 + 6 it would be 13 then add 30.
1 + any whole number over 8 will change the tens digit
2 + any whole number over 7 will change the tens digit
3 + any whole number over 6 will change the tens digit
4 + any whole number over 5 will change the tens digit
5 + any whole number over 4 will change the tens digit
6 + any whole number over 3 will change the tens digit
7 + any whole number over 2 will change the tens digit
8 + any whole number over 1 will change the tens digit
9+ any whole number over 0 will change the tens digit
ect
When you add tens to the tens digit and ones it goes ten more.
Look at the digit to the right of the tens digit. If it is 5 or more, add one to the digit and add zeros in the end. Otherwise it will be 4 or less and so leave the number alone.
Look at the tens digit. If it is 5 or more, add 100 to 9876. Then replace all the digits to the right of the hundreds digit (the tens and units digits) by zeros. The answer is therefore 9900
9 is in the hundreds place. The tens digit will determine whether you round this up (in which case it would become 10, which would mean zero and add 1 to the thousands digit). The tens digit is 7, so the 9 rounds up and rounded it is 5000
To find the product of 23 and 18, you would use the standard multiplication method. Start by multiplying the units digit of the first number (3) by the units digit of the second number (8), which equals 24. Write down the 4 and carry over the 2. Then, multiply the units digit of the first number by the tens digit of the second number, and vice versa, and add the carried over digit. Finally, multiply the tens digit of the first number by the tens digit of the second number and add it to the total. The result of 23 x 18 is 414.
When you add tens to the tens digit and ones it goes ten more.
The answer would be 37.
Such a number does not exist.
The answer depends on what the tens digit is greater than, and what the ones digit does then.
Add the last digit (units digit) to twice the previous digit (tens digit). If this sum is divisible by 4, so is the original number.
Look at the digit to the right of the tens digit. If it is 5 or more, add one to the digit and add zeros in the end. Otherwise it will be 4 or less and so leave the number alone.
0
The tens' digit is 6. If what follows it is less than 5 then replace every digit following the tens' digit by 0s. If what follows is bigger than 5 then add 1 to the tens' digit and replace every digit following the tens' digit by 0s. If it is exactly 5 then make sure that the tens' digit is even and replace everything after it by 0s. Many naive teachers require that you round up (add 1 etc) when the next digit is 5. This introduces an upward bias and in statistically unsound. The solution is to round to odd or round to even. (See link). Mathematically, they are equivalent but, judging by the latter seems to be winning. It is the default mode in IEEE 754.
Look at the tens digit. If it is 5 or more, add 100 to 9876. Then replace all the digits to the right of the hundreds digit (the tens and units digits) by zeros. The answer is therefore 9900
9 is in the hundreds place. The tens digit will determine whether you round this up (in which case it would become 10, which would mean zero and add 1 to the thousands digit). The tens digit is 7, so the 9 rounds up and rounded it is 5000
the answer is 1058 simply add it up?
To find the product of 23 and 18, you would use the standard multiplication method. Start by multiplying the units digit of the first number (3) by the units digit of the second number (8), which equals 24. Write down the 4 and carry over the 2. Then, multiply the units digit of the first number by the tens digit of the second number, and vice versa, and add the carried over digit. Finally, multiply the tens digit of the first number by the tens digit of the second number and add it to the total. The result of 23 x 18 is 414.