The answer is 43 and the reason why the tens digit changes is because 7 + anything over 2 will change the digit. If just added 7 + 6 it would be 13 then add 30.
1 + any whole number over 8 will change the tens digit
2 + any whole number over 7 will change the tens digit
3 + any whole number over 6 will change the tens digit
4 + any whole number over 5 will change the tens digit
5 + any whole number over 4 will change the tens digit
6 + any whole number over 3 will change the tens digit
7 + any whole number over 2 will change the tens digit
8 + any whole number over 1 will change the tens digit
9+ any whole number over 0 will change the tens digit
ect
When you add tens to the tens digit and ones it goes ten more.
Look at the digit to the right of the tens digit. If it is 5 or more, add one to the digit and add zeros in the end. Otherwise it will be 4 or less and so leave the number alone.
Look at the tens digit. If it is 5 or more, add 100 to 9876. Then replace all the digits to the right of the hundreds digit (the tens and units digits) by zeros. The answer is therefore 9900
9 is in the hundreds place. The tens digit will determine whether you round this up (in which case it would become 10, which would mean zero and add 1 to the thousands digit). The tens digit is 7, so the 9 rounds up and rounded it is 5000
1. None of the digits before the tens' digit (4) should change. 2. Identify the digit in the tens' place (3). 3. Identify the digit in the units' place. 4a. If it is 0, leave the tens' digit unchanged 4b. If it is 1, 2, 3 or 4 then the number needs to be rounded down. So replace the units digit by 0. 4c. If it is 6, 7, 8 or 9 then the number needs to be rounded up. So increase the tens' digit by 1 (from 3 to 4), and replace the units digit by 0. 4d. If it is 5 then, in order to avoid introducing bias, you need to round up half the time and round down half the time. The way to do this is to make the tens' digit even: if it is already even then do nothing, if it is odd then add 1. And replace the units' digit by 0. In this case the answer is 440. Two things to bear in mind: Many schools opt for the naive approach of applying rule 4b (instead of 4d) for the digit 5. In the case of rule 1, you need to bear in mind any carry over from rounding up the tens.
When you add tens to the tens digit and ones it goes ten more.
The answer would be 37.
Such a number does not exist.
The answer depends on what the tens digit is greater than, and what the ones digit does then.
Add the last digit (units digit) to twice the previous digit (tens digit). If this sum is divisible by 4, so is the original number.
Look at the digit to the right of the tens digit. If it is 5 or more, add one to the digit and add zeros in the end. Otherwise it will be 4 or less and so leave the number alone.
0
The tens' digit is 6. If what follows it is less than 5 then replace every digit following the tens' digit by 0s. If what follows is bigger than 5 then add 1 to the tens' digit and replace every digit following the tens' digit by 0s. If it is exactly 5 then make sure that the tens' digit is even and replace everything after it by 0s. Many naive teachers require that you round up (add 1 etc) when the next digit is 5. This introduces an upward bias and in statistically unsound. The solution is to round to odd or round to even. (See link). Mathematically, they are equivalent but, judging by the latter seems to be winning. It is the default mode in IEEE 754.
Look at the tens digit. If it is 5 or more, add 100 to 9876. Then replace all the digits to the right of the hundreds digit (the tens and units digits) by zeros. The answer is therefore 9900
9 is in the hundreds place. The tens digit will determine whether you round this up (in which case it would become 10, which would mean zero and add 1 to the thousands digit). The tens digit is 7, so the 9 rounds up and rounded it is 5000
the answer is 1058 simply add it up?
You first add the units, then the tens.