2 tens and 13 ones add up to 33 because 10 +10 +13 = 33.
The answer is 43 and the reason why the tens digit changes is because 7 + anything over 2 will change the digit. If just added 7 + 6 it would be 13 then add 30. 1 + any whole number over 8 will change the tens digit 2 + any whole number over 7 will change the tens digit 3 + any whole number over 6 will change the tens digit 4 + any whole number over 5 will change the tens digit 5 + any whole number over 4 will change the tens digit 6 + any whole number over 3 will change the tens digit 7 + any whole number over 2 will change the tens digit 8 + any whole number over 1 will change the tens digit 9+ any whole number over 0 will change the tens digit ect
4000
Well, honey, to get from 212 to 572, you need to add 360. And since each ten is worth 10, you gotta add 36 tens. So, there you have it, add 36 tens to 212 ones and 100 to get to 572.
Look at the digit to the right of the tens digit. If it is 5 or more, add one to the digit and add zeros in the end. Otherwise it will be 4 or less and so leave the number alone.
The answer would be 37.
The answer depends on what the tens digit is greater than, and what the ones digit does then.
0
455
It increases by 1 unless it was a 9. In that case, it becomes a 0 and the previous digit (to the left) increases by 1. Unless that was a 9 in which case ... and so on.
2 tens and 13 ones add up to 33 because 10 +10 +13 = 33.
The answer is 43 and the reason why the tens digit changes is because 7 + anything over 2 will change the digit. If just added 7 + 6 it would be 13 then add 30. 1 + any whole number over 8 will change the tens digit 2 + any whole number over 7 will change the tens digit 3 + any whole number over 6 will change the tens digit 4 + any whole number over 5 will change the tens digit 5 + any whole number over 4 will change the tens digit 6 + any whole number over 3 will change the tens digit 7 + any whole number over 2 will change the tens digit 8 + any whole number over 1 will change the tens digit 9+ any whole number over 0 will change the tens digit ect
4000
When you multiply a two digit number by another, you use the distributive property because you basically are taking the tens digits times both the other tens digit and the ones digit, then the ones digit times both the other tens and other ones digits. That sounds confusing, I know, but I'll explain. If you're taking 12 times 25, you are basically doing the problem (10+2) x (20+5). You take ten times twenty, then ten times five, then two times twenty, then two times five, and add them all together.
Add the last digit (units digit) to twice the previous digit (tens digit). If this sum is divisible by 4, so is the original number.
Consider the example 234 x 26.When multiplying out, you do the ones digit first, then the tens digit:ones: 234 x 6 = 1404tens: 234 x 2 = 468and then add the results together.However, the value of the tens digit is the_digit x 10. So in this example, the tens digit is not worth two (2) but twenty (20 = 2 x 10). Thus the correct value of multiplying by the tens digit is:234 x 2 x 10 = 468 x 10 = 4680(The correct sum is: 234 x 26 = 1406 + 4680 = 6084)So when multiplying by the tens digit there will be a zero (0) on the end.Similarly when multiplying by a hundreds digit there will be two zeros (00) on the end.To avoid forgetting to do this, the zero(s) is(are) normally written in first before doing the multiplication by the tens (hundreds, etc) digit.
Look at the digit to the right of the tens digit. If it is 5 or more, add one to the digit and add zeros in the end. Otherwise it will be 4 or less and so leave the number alone.