answersLogoWhite

0


Best Answer

-- The roots of a quadratic equation are the values of 'x' that make y=0 .

-- When you graph a quadratic equation, the graph is a parabola.

-- The points on the parabola where y=0 are the points where it crosses the x-axis.

-- If it doesn't cross the x-axis, then the roots are complex or pure imaginary,

and you can't see them on a graph.

User Avatar

Wiki User

14y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Where do you find the roots when looking at a parabola?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Other Math

What are the roots of a parabola?

I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.


How do you do a parabola?

A parabola is a graph of a 2nd degree polynomial function. Two graph a parabola, you must factor the polynomial equation and solve for the roots and the vertex. If factoring doesn't work, use the quadratic equation.


To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?

To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.


How do you solve quadratics using graphing?

Recall that the graph of a linear equation in two variables is a line. The equation y = ax^2 + bx + c, where a, b, and c are real numbers and a is different than 0 represents a quadratic function. Its graph is a parabola, a smooth and symmetric U-shape. 1. The axis of symmetry is the line that divides the parabola into two matching parts. Its equation is x = -b/2a 2. The highest or lowest point on a parabola is called the vertex (also called a turning point). Its x-coordinate is the value of -b/2a. If a > 0, the parabola opens upward, and the vertex is the lowest point on the parabola. The y-coordinate of the vertex is the minimum value of the function. If a < 0, the parabola opens downward, and the vertex is the highest point on the parabola. The y-coordinate of the vertex is the maximum value of the function. 3. The x-intercepts of the graph of y = ax^2 + bx + c are the real solutions to ax^2 + bx + c = 0. The nature of the roots of a quadratic function can be determined by looking at its graph. If you see that there are two x-intercepts on the graph of the equation, then the equation has two real roots. If you see that there is one x-intercept on the graph of the equation, then the equation has one real roots. If you see that the graph of the equation never crosses the x-axis, then the equation has no real roots. The roots can be used further to determine the factors of the equation, as (x - r1)(x -r2) = 0


Parabola is the point at which the parabola is at its lowest or highest point?

A parabola is NOT a point, it is the whole curve.

Related questions

What are the roots of a parabola?

I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.


Does a parabola always have roots and a vertex?

An x2 parabola will always have one vertex, but depending on the discriminant of the function (b2-4ac) the parabola will either have 2 roots (it crosses the x-axis twice), 1 repeating root (the parabola meets the x-axis at a single point), or no real roots (the parabola doesn't meet the x-axis at all)


How do you find a solution of a parabola?

The "solution" depends on what the question is.If you mean the roots, and if the equation of the parabola isy = ax^2 + bx + c then the roots are[-b +/- sqrt(b^2-4ac)]/(2a)


How do you find the zeros in a parabola?

If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)


What are the steps solving a parabola?

The answer will depend onwhat you mean by "solving a parabola". A parabola has a directrix and a focus, a turning point, 0 1 or 2 roots and so on. Which of these is "solving"?The answer will depend onwhat you mean by "solving a parabola". A parabola has a directrix and a focus, a turning point, 0 1 or 2 roots and so on. Which of these is "solving"?The answer will depend onwhat you mean by "solving a parabola". A parabola has a directrix and a focus, a turning point, 0 1 or 2 roots and so on. Which of these is "solving"?The answer will depend onwhat you mean by "solving a parabola". A parabola has a directrix and a focus, a turning point, 0 1 or 2 roots and so on. Which of these is "solving"?


How do you solve for roots in a parabola?

If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)


What is the root of a parabola?

In analytical geometry, the roots of a parabola are the x-values (if any) for which y = 0.


What is a parabola and quadratic?

A parabola is a line with one curve, that usually crosses the x-axis of a graph twice (unless the roots are imaginary). To find the roots, set y to zero and use the quadratic formula (-b±√b^2-4AC/2A)


What is the average of the two roots of quadratic equation?

In a quadratic y = ax² + bx + c, the roots are where y = 0, and the parabola crosses the x-axis. The average of these two roots is the x coordinate of the vertex of the parabola.


Parts of a parabola?

There's the vertex (turning point), axis of symmetry, the roots, the maximum or minimum, and of course the parabola which is the curve.


What is the graph of a quadratic formula?

In general, quadratic equations have graphs that are parabolas. The quadratic formula tells us how to find the roots of a quadratic equations. If those roots are real, they are the x intercepts of the parabola.


How do you do a parabola?

A parabola is a graph of a 2nd degree polynomial function. Two graph a parabola, you must factor the polynomial equation and solve for the roots and the vertex. If factoring doesn't work, use the quadratic equation.