0
-- The roots of a quadratic equation are the values of 'x' that make y=0 .
-- When you graph a quadratic equation, the graph is a parabola.
-- The points on the parabola where y=0 are the points where it crosses the x-axis.
-- If it doesn't cross the x-axis, then the roots are complex or pure imaginary,
and you can't see them on a graph.
What else can I help you with?
What are the roots of a parabola?
I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.
How do you do a parabola?
A parabola is a graph of a 2nd degree polynomial function. Two graph a parabola, you must factor the polynomial equation and solve for the roots and the vertex. If factoring doesn't work, use the quadratic equation.
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
How do you solve quadratics using graphing?
Recall that the graph of a linear equation in two variables is a line. The equation y = ax^2 + bx + c, where a, b, and c are real numbers and a is different than 0 represents a quadratic function. Its graph is a parabola, a smooth and symmetric U-shape. 1. The axis of symmetry is the line that divides the parabola into two matching parts. Its equation is x = -b/2a 2. The highest or lowest point on a parabola is called the vertex (also called a turning point). Its x-coordinate is the value of -b/2a. If a > 0, the parabola opens upward, and the vertex is the lowest point on the parabola. The y-coordinate of the vertex is the minimum value of the function. If a < 0, the parabola opens downward, and the vertex is the highest point on the parabola. The y-coordinate of the vertex is the maximum value of the function. 3. The x-intercepts of the graph of y = ax^2 + bx + c are the real solutions to ax^2 + bx + c = 0. The nature of the roots of a quadratic function can be determined by looking at its graph. If you see that there are two x-intercepts on the graph of the equation, then the equation has two real roots. If you see that there is one x-intercept on the graph of the equation, then the equation has one real roots. If you see that the graph of the equation never crosses the x-axis, then the equation has no real roots. The roots can be used further to determine the factors of the equation, as (x - r1)(x -r2) = 0
Parabola is the point at which the parabola is at its lowest or highest point?
A parabola is NOT a point, it is the whole curve.
What are the roots of a parabola?
I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.
Does a parabola always have roots and a vertex?
An x2 parabola will always have one vertex, but depending on the discriminant of the function (b2-4ac) the parabola will either have 2 roots (it crosses the x-axis twice), 1 repeating root (the parabola meets the x-axis at a single point), or no real roots (the parabola doesn't meet the x-axis at all)
How do you find a solution of a parabola?
The "solution" depends on what the question is.If you mean the roots, and if the equation of the parabola isy = ax^2 + bx + c then the roots are[-b +/- sqrt(b^2-4ac)]/(2a)
How do you find the zeros in a parabola?
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
What are the steps solving a parabola?
The answer will depend onwhat you mean by "solving a parabola". A parabola has a directrix and a focus, a turning point, 0 1 or 2 roots and so on. Which of these is "solving"?The answer will depend onwhat you mean by "solving a parabola". A parabola has a directrix and a focus, a turning point, 0 1 or 2 roots and so on. Which of these is "solving"?The answer will depend onwhat you mean by "solving a parabola". A parabola has a directrix and a focus, a turning point, 0 1 or 2 roots and so on. Which of these is "solving"?The answer will depend onwhat you mean by "solving a parabola". A parabola has a directrix and a focus, a turning point, 0 1 or 2 roots and so on. Which of these is "solving"?
How do you solve for roots in a parabola?
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
What is a parabola and quadratic?
A parabola is a line with one curve, that usually crosses the x-axis of a graph twice (unless the roots are imaginary). To find the roots, set y to zero and use the quadratic formula (-b±√b^2-4AC/2A)
What is the root of a parabola?
In analytical geometry, the roots of a parabola are the x-values (if any) for which y = 0.
What is the average of the two roots of quadratic equation?
In a quadratic y = ax² + bx + c, the roots are where y = 0, and the parabola crosses the x-axis. The average of these two roots is the x coordinate of the vertex of the parabola.
Parts of a parabola?
There's the vertex (turning point), axis of symmetry, the roots, the maximum or minimum, and of course the parabola which is the curve.
What is the graph of a quadratic formula?
In general, quadratic equations have graphs that are parabolas. The quadratic formula tells us how to find the roots of a quadratic equations. If those roots are real, they are the x intercepts of the parabola.
How are the vertices of the parabolas related to the equation of the quadratic function?
Suppose the equation of the parabola is y = ax2 + bx + c where a, b, and c are constants, and a ≠0. The roots of the parabola are given by x = [-b ± sqrt(D)]/2a where D is the discriminant. Rather than solve explicitly for the coordinates of the vertex, note that the vertical line through the vertex is an axis of symmetry for the parabola. The two roots are symmetrical about x = -b/2a so, whatever the value of D and whether or not the parabola has real roots, the x coordinate of the vertex is -b/2a. It is simplest to substitute this value for x in the equation of the parabola to find the y-coordinate of the vertex, which is c - b2/2a.
