A perpendicular line has the negative reciprocal of the slope. The perpendicular line has a slope of 1/2 y=1/2 + 3 The 3 or y-intercept can really be any number though.
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
6
When two lines are perpendicular, their slopes are negative reciprocals. In the example, the perpendicular to y= (1/21) x would be y = -21 x For y = 2x, the perpendicular would be y= -½ x You invert the fraction and change the sign.
If you mean y = -13x then the slope of the line perpendicular to it is 1/13
If -14 is the y intercept then it is: y = -1/13x -14
That equation represents only one line. y - 11 = 13x - 7 y = 13x + 4 The slope is 13.
That equation represents only one line. y - 11 = -13x - 7 y = -13x + 4 The slope is -13.
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 = -13/2(x-0.5) => 2y-4 = -13x+6.5 => 2y = -13x+10.5
A line perpendicular to the y-axis is a horizontal line (slope = 0) and is of the form y = b Therefore the required line is y = 5
y=-2 is parallel to the x-axis and perpendicular to the y-axis.
Given y = 2x the slope of that line is simply 2, A perpendicular line would have the negative inverse of 2, -1/2 or -.5 thus y = 2x is perpendicular to y = -.5x Y = -(1/Mx) + b is perpendicular to: Y= Mx + b
If you mean: y = 6x+2 then its perpendicular line is -1/6
It would be perpendicular to a line with the equation Y = 1/8 X.
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 =-13/2(x-0.5) => 2y-4 = -13x+6.5 => 2y = -13x+10.5 Therefore the perpendicular bisector equation is: 2y = -13x+10.5
Slope of a line perpendicular to x-y=16