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To find which has imaginary roots, use the discriminant of the quadratic formula (b2 - 4ac) and see if it's less than 0. (The quadratic formula corresponds to general form of a quadratic equation, y = ax2 + bx + c)

A) x2 - 1 = 0

= 0 - 4(1)(-1) = 4

Therefore, the roots are not imaginary.

B) x2 - 2 = 0

= 0 - 4(1)(-2) = 8

Therefore, the roots are not imaginary.

C) x2 + x + 1 = 0

= 1 - 4(1)(1) = -3

Therefore, the roots are imaginary.

D) x2 - x - 1 = 0

= 1 - 4(1)(-1) = 5

Therefore, the roots are not imaginary.

The equation x2 + x + 1 = 0 has imaginary roots.

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Q: Which equation has imaginary roots a.x2-1 equals 0 b.x2-2 equals 0 c.x2 plus x plus 1 equals 0 d.x2-x-1 equals 0?
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