(-2,7),(3,-8) first you find the slope:
m=y2-y1
_____
x2-x1
m=-8-7
_____
3+2
m=-3
then you find the y-intercept:
y=mx+b
7=((-3)(-2))+b
7=6+b
-6 -6
1=b
so its y=-3x=1
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
which equation has a slope of -1/2 and a graph that passes through (-3,4)?
y = -4x
It is: y = -2x
Y= -3x + 8
It is: y = 2x+11
If you mean a slope of -1 then it is: y = -x+5
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
I will assume you mean the line passes through (0, -24).The equation of a line is y=mx+cSince the line is horizontal, we know m is 0. Since m is zero, the x term disappears, leaving us with:y = cSince we know c (the y-intercept) to be -24, the equation of this line is simply:y = -24
If you mean a slope of -1 then it is: y = -x+5
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
y = 0. You can get this from the slope-intercept equation of the line.
which equation has a slope of -1/2 and a graph that passes through (-3,4)?
We know that its slope is negative, but without an equation or some points the line passes through we can't determine the actual value of the slope.
sda
Find an equati find an equation for the line perpendicular to the line 8x - 8 y equals negative 2 having the same Y intercept as -6x + 2 y equals negative 8
The equation of the line works out as: y = -3x+29