A palindrome reads the same forward and in reverse. This tells me that at least
the first digit and the last digit must be the same. So it's not possible to have a
6-digit palindrome "with no same digits".
The largest 6-digit palindrome, with just enough repetition of digits to make it a
palindrome and no more, would be 987,789 .
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84.42 or 42.21
If you realize that a 4 digit palindrome is basically a two digit number followed by it's own reverse, you can re-phrase this question as 'how many two digit numbers are there?' Which would then mean that (if you're considering zeros as digits without a non-zero leading term) there would be a 4 digit palindrome 0000 for the two digit 00; a four digit 0110 for the two digit 01; 0220, 02; etc etc. So the number of four digit palindromes would be the same as the quantity of whole numbers from 00 to 99. So I believe the total answer to your question would be 100.
Well, isn't that a happy little question! To find out how many five-digit even palindromes there are, let's break it down. A five-digit number has the form ABCBA, where A, B, and C are digits. Since the number is even, A must be even. So, there are 5 options for A (0, 2, 4, 6, 8), 10 options for B (0-9), and 1 option for C. Multiply these options together and you'll find the total number of five-digit even palindromes.
no it does not thank you
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