How many five digit even palindromes are there?

Answer 1

Well, isn't that a happy little question! To find out how many five-digit even palindromes there are, let's break it down. A five-digit number has the form ABCBA, where A, B, and C are digits. Since the number is even, A must be even. So, there are 5 options for A (0, 2, 4, 6, 8), 10 options for B (0-9), and 1 option for C. Multiply these options together and you'll find the total number of five-digit even palindromes.

Answer 2

A five-digit even palindrome has the form ABCBA, where A, B, and C are digits. Since the number is even, the units digit (A) must be even. There are 5 choices for A (0, 2, 4, 6, 8), 10 choices for B (0-9), and 9 choices for C (0-9 excluding B). Therefore, the total number of five-digit even palindromes is 5 x 10 x 9 = 450.

Answer 3

Oh, dude, let me break it down for you. So, a five-digit even palindrome would have its first and last digits the same, right? And since it's even, the last digit can't be an odd number. So, you've got 5 choices for the first digit (1-9), 10 choices for the second digit (0-9), and 1 choice for the last digit (the same as the first). So, that's 5 x 10 x 1 = 50 five-digit even palindromes. Easy peasy!

Answer 4

There are 400.

Assuming the number must be at least 10,000, then:

In a 5 digit palindrome, the first and last digits must be the same, and the second and fourth digits must be the same; and:

For the first and last digit there is a choice of 4 digits {2, 4, 6, 8};

For each of these there is a choice of 10 digits {0, 1, ..., 9} for the second and fourth digits;

For each of the above choices these is a choice of 10 digits {0, 1, ..., 9} for the third digit;

Making 4 x 10 x 10 = 400 possible even 5 digit palindromes.