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The smallest number that will can be divided by 2, 3, 4, 5, 6 and 7 is 420.
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To find the smallest possible number that satisfies both conditions, we need to find the least common multiple (LCM) of 4 and 7, which is 28. Adding 2 to the LCM gives us the smallest number that leaves a remainder of 2 when divided by both 4 and 7. Therefore, the smallest possible number is 30.
The smallest number that can be divided by 2 3 4 5 6 7 8 and always give you a remainder of 1 is 841
To find the smallest number divisible by 7 and 6 with two odd digits, we need to consider the least common multiple (LCM) of 7 and 6, which is 42. The smallest two-digit odd number is 11. Therefore, the smallest number that meets all these criteria is 11 x 42, which equals 462.