a.357404
b.114345
c.991111
d.135792
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8 of the numbers less than 660 are divisible by 5 and 11 but not 3. All numbers divisible by 5 and 11 are multiples of their lcm; lcm(5, 11) = 55 All numbers divisibile by 5, 11 and 3 are multiples of their lcm; lcm(5, 11, 3) = 165 659 ÷ 55 = 11 54/55 → 11 numbers less than 660 are divisible by 5 and 11 659 ÷ 165 = 3 164/165 → 3 numbers less than 660 are divisible by 5, 11 and 3 → of the 11 numbers less than 660 divisible by 5 and 11, 3 are also divisible by 3 → 11 - 3 = 8 numbers less than 660 are divisible by 5 and 11 but not 3,.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
Not exactly because it will have a remainder
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
no, it is not. You can check by adding the digits and if divisible by 3 so is the number. In your case 2 + 9 + 3 = 14 which is not divisible by 3