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Opposite angles of quadrilaterals in general can vary over quite a range of degrees. In order for a quadrilateral to be a parallelogram, two sets of parallel lines intersect. Imagine a parallelogram resting on its base. Focus on one of the base interior angles. Now flip the parallelogram so that its top is now the base. The shapes will be completely congruent, both in angle size and lengths of sides. Parallelogram is simply a special class of quadrilateral, and this property is part of how parallelograms are defined.

Alternative Answer:

It is rather difficult to prove a geometric proposition while working within the limitations of this browser! But here goes:

Call the parallelogram is ABCD with AB parallel to DC horizontal, and AD parallel to BC.

Consider AD and BC which are parallel, with transversal DC. Then the interior angles on the same side are supplementary. That is, angles ADC and DCB are supplementary.

Now consider AB and DC which are parallel, with transversal AD. Then the interior anlges on the same side are supplementary. That is, angles BAD and ADC are supplementary.

So in the above two paragraphs we have shown that angles ADC + DCB = BAD + ADC

therefore angle DCB = angle BAD [subtracting angle ADC from both sides]

that is, one pair of opposite angles are equal.

You can prove the other pair is equal either by the fact that they are supplementary to these, or by the symmetry of the argument.

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12y ago
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Q: Why are opposite angles in a parallelogram equal?
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