the answer is 8x0/1
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An 8 bit binary code is a code that is 8 digits long. It would look like this: 00110010
Octet
1011 in binary code is 11 in 'ordinary' (decimal) code. In the table, the top row shows the value of each digit, which depends on its position. The row below that is our binary number. ----------------- | 8 | 4 | 2 | 1 | ----------------- | 1 | 0 | 1 | 1 | ----------------- So the value of 1011 is 8 + 0 + 2 + 1 = 11 See the related link, Binary Numbers, below.
I do not believe that is a valid binary number. All binary numbers must be divisible by 8
No, 0110101 is a 7-bit binary number. In an 8-bit binary number, there would be 8 digits (0s or 1s) representing a total of 256 possible values (2^8). The given number has only 7 digits, so it falls short of being an 8-bit binary number.