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Why can't b 0?

Updated: 4/28/2022
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9y ago

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cause can

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9y ago

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Q: Why can't b 0?
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How -A multiplied by -B equals plus AB was determined and when?

A*(B-B) = A*0 = 0 Expanding the left hand side, using the distributive property, A*B + A*(-B) = 0 That is, A*B and A*(-B) are additive inverses. Next, (A-A)*(-B) = 0*(-B) = 0 Expanding, A*(-B) + (-A)*(-B) = 0 Therefore A*(-B) and (-A)*(-B) are additive inverses But, from above, the additive inverse of -A*B is A*B Therefore (-A)*(-B) = A*B It is not known when this was proven.


If the product of two numbers is 0 does one of the numbers have to be 0?

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How can you prove if a and b are real numbers then a plus b-a equals b?

Real numbers are commutative under addition (and subtraction) so a + b - a = a - a + b The set of Real numbers includes an additive identity, 0, such that a - a = 0 so a - a + b = 0 + b The additive identity also has the property that 0 + b = b [= b + 0] so 0 + b = b


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A=B , A-B=B-B , A-B =0 B=C , B-B=C-B, 0=C-B So A-B=0 but also C-B=0 A-B=C-B ...add +b ...A-B+B=C-B+B , A=C


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Presumably you mean is it true that: ( A nor B ) nor C == A nor ( B nor C ) ? No. Let's make a table: A B C (A nor B) (B nor C) [ (A nor B ) nor C ] [ A nor ( B nor C ) ] 0 0 0 1 1 0 0 0 0 1 1 0 0 1 .... So you see right away for A=0, B=0, and C=1 it doesn't work.


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A+A*b does not mean A plus Ab the operation signified by "+" is called "or" the operation signified by "*" is called "and" there are four possible outcomes of a+a*b if a=1 and b=1 the result is 1 if a=1 and b=0 the result is 1 if a=0 and b=1 the result is 0 if a=0 and b=0 the result is 0 a+a*b is 1 if a is 1 and a+a*b is 0 if a is 0 regardless of the value of b thus a+a*b=a Q.E.D.


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