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What would cause the calorimeter efficiency to be less than 100 percent?
why is the efficiency of a calorimeter less than 100%
Is a machine physically possible that has an efficiency greater than 100 percent?
Not if the laws of physics - specifically thermodynamics - are correct.
Why is mechanical efficiency always less than 100 percent?
That simply means that some energy is lost, due to friction and other causes.
What is the formula for calculating efficiency?
General formula for calculating efficiency is given by Efficiency = (output / input) * 100 It is denoted by greek letter Eta Efficiency cannot be more than 100%.
What is 3 percent 100 g?
Percent means out of 100 → 3 percent of 100 g = 3/100 × 100 g = 3 g
Does a refrigerator have 100 percent efficiency?
nothing has 100% efficiency.
Can a car have a 100 percent efficiency?
No. Nothing mechanical can ever have a 100% efficiency by any physical evaluation.
What would cause the calorimeter efficiency to be less than 100 percent?
why is the efficiency of a calorimeter less than 100%
How does the output work compare to the input work for a machine that has an efficiency equal to 100 percent?
If a machine has 100 percent efficiency, the output work = the input work. That's actually basically what the efficiency of a machine is - output work / input work * 100.
When efficiency is at 100 percent it is known as what with power factor?
"Unity"
An ideal machine would have an efficiency of?
A ideal machine would have an efficiency of 100 percent. For this to be possible, the amount of energy output by the machine would equal the amount of energy input. Because all machines have physical parts, some energy is lost to friction, heat dissipation, or other factors, so no machine can be an ideal machine.
What is the formula to calculate percent efficiency?
(work out/work in) x 100
Why a normal machine could not have the mechanical efficiency of 100?
Because there is always going to be friction, the efficiency of any machine will always be less then 100 percent.
What is the efficiency of a machine that requires 100 joules of input energy to do 35 joules of useful work?
The efficiency of the machine can be calculated by dividing the useful work output by the total input energy and multiplying by 100. In this case, the efficiency would be (35/100) * 100 = 35%.
What would a machine that had 100 percent mechanical efficiency be called?
A machine with 100 percent mechanical efficiency would be called an ideal machine, as it would have no energy losses due to friction, heat, or other inefficiencies.
How can convert efficiency to percent?
Work done = (force * distance)>Efficiency (%) = (Work done output / Work done input) * 100
What is the percent efficiency if a man expends 100 J of work and the work produced is 80 J?
100*80/100 = 80%
