from 3 digits (10x10) to 4 digits (99X99)
A number is divisible by 3 if the sum of its digits is divisible by 3.
There are 2 digits in 30. They are 3 and 0.
3 to 5 digits
There are five significant digits.
The digits of 330 are 3, 3 and 0, so the sum of those digits means add them up - 3+3+0=6
215
249 + 318 = 567
This is from Weekly Homework Sheet (3).What 3 digits are in the thousands period? 8279,827,273
999 - 100 = 899
There is no solution to this problem. If each digit can be used once only then we have 5 odd numbered digits (1,3,5,7,9) and 4 even numbered digits (2,4,6,8). To create the two numbers that are added together requires the following combinations of digits. 5 Odd & 1 Even ....when added these will generate 2 Even digits & 1 Odd digit but the remaining digits are 3 Even. 4 Odd & 2 Even. These will generate 3 Even digits OR 1 Even digit & 2 Odd digits but the remaining digits are 1 Odd & 2 Even. 3 Odd & 3 Even. These generate 3 Odd digits OR 2 Even & 1 Odd digits but the remaining digits are 2 Odd & 1 Even. 2 Odd & 4 Even. These generate 3 Even digits OR 2 Odd & 1 Even digits but the remaining digits are 3 Odd & no Even.
from 3 digits (10x10) to 4 digits (99X99)
120 There are 6 digits in total. The numbers with 3 digits, with all digits distinct from each other, are the permutations of the 6 digits taken 3 at a time, and therefore there are 6*5*4 = 120 of them.
3 significant digits.
No, it has 3 significant digits.
It has 3 significant digits.
by using decimals