This first number in an ordered pair is x. And since x is always -5, all these work. (-5,0),(-5,1),(-5,2),(-5,3),(-5,4)
yes, numbers ending in a 5 or 0 are always divisible by 5.
-25A negative times a positive will always be a negative.
5000 = 5 x 1000 & 1000 = 10 x 10 x 10 = 2^3 x 5^3 Hence in exp in exponential form 5^(1) x 2^3 x 5^3 Remember for exponents, when multiplying with a common coefficient, you add the exponents(indices) Hence 2^3 x 5^(1 + 3) = 2^3 x 5^4
no
you use BIDMAS Brackets Indices (Division Multiplication) (Addition Subtraction) the brackets always come first then Indices (to the power of) them multiply and divine have the same equality either and adding and subtracting are the same. so you would multiply 8x2=16 then you subtract 5 16-5=11.
Exponents are the same as powers or indices and so:- When multiplying terms add the indices: y2*y6 = y8 When dividing terms subtract the indices: x6/x2 = x4 Powers of powers multiply the the indices: (p2)3 = p6 Square root of: d8 = d8/2 = d4 Cube root of: p15 = p15/3 = p5 Remember:- Anything to the power of 0 is 1: x0 = 1 Anything to the power of 1 is just itself: x1 = x 1 raised to any power is just 1: 110 = 1
2 x 5 x 37
It is: 2*5*7 = 70 and no indices are needed
22 x 3 x 5
It means to write out your answers in index or indices format as for example 5*5 = 25 which is the same as 52
God is always at work. John 5:17
It is: 2 times 3^2 times 5 = 90 no indices are needed for 2 and 5
No indices are needed because as a product of its prime factors: 3*5*7 = 105
0.8333
Natasha Laws Mick is 5' 5".
This is relatively easy to solve, only requires application of the laws of indices. (x+5)1/5 - (x+5)6/5 = 0 => (x+5)1/5 - (x+5)(x+5)1/5 = 0 => (x+5)1/5 (1 - (x+5)) = 0 => -(x+5)1/5 (x+4)=0 since the expression equals 0 one term or the other has to be 0 therefore x= -4 or x= -5