80 is divisible by 2 because it's an even number; nevertheless, maybe it's because 2+2+2+2=8, or 2x4=8. So, it's divisible because 2x4=8, and 0 is 0. So 80 divided by 2 is 40. Plus it's math. :D
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No; it is divisible only by its factors (1, 2, 4, 5, 8, 10, 16, 20, 40, and 80).
The first number is 80
160 is divisible by all three numbers, 10, 2, and 5. 160 / 10 = 16 160 / 2 = 80 160 / 5 = 32
There are 80 such numbers.
A number is a multiple of 80 if the last 4 digits are a multiple of 80 The 1,000s digit is even and the last 3 digits are a multiple of 80 The 1,000s digit is odd and the last 3 digits are 40 times an odd number It also works if the number is a multiple of 5 and 16 at the same time because 80 = 2^4 x 5 = 16 x 5