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Q: Why is the period of secant 2 pi?

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2*Pi

2pi

The function sec(x) is the secant function. It is related to the other functions by the expression 1/cos(x). It is not the inverse cosine or arccosine, it is one over the cosine function. Ex. cos(pi/4)= sqrt(2)/2 therefore secant is sec(pi/4)= 1/sqrt(2)/2 or 2/sqrt(2).

2

Secant(3pi/4) = 1/cos(3pi/4) = 1/[-1/sqrt(2)] = -sqrt(2)

Related questions

2*Pi

2*pi radians.

It is 2*sqrt(3)/3.

Since secant theta is the same as 1 / cosine theta, the answer is any values for which cosine theta is zero, for example, pi/2.

2pi

2PI

The secant of an angle is the reciprocal of the cosine of the angle. So the secant is not defined whenever the cosine is zero That is, whenever the angle is a multiple of 180 degrees (or pi radians).

Trigonometric functions are periodic - they repeat after a period of pi, or 2 x pi.Trigonometric functions are periodic - they repeat after a period of pi, or 2 x pi.Trigonometric functions are periodic - they repeat after a period of pi, or 2 x pi.Trigonometric functions are periodic - they repeat after a period of pi, or 2 x pi.

The function sec(x) is the secant function. It is related to the other functions by the expression 1/cos(x). It is not the inverse cosine or arccosine, it is one over the cosine function. Ex. cos(pi/4)= sqrt(2)/2 therefore secant is sec(pi/4)= 1/sqrt(2)/2 or 2/sqrt(2).

It is 360 degrees.

The period of the tangent function is PI. The period of y= tan(2x) is PI over the coefficient of x = PI/2

tan^2(x) + 1 = sec^2(x) for x not equal to odd multiples of pi/2 radians (90 deg).

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