Q: What is the period of y equals tan2x?

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It depends on the domain of x.

tan(2x) = 2tanx/(1 - tan2x) So tan(2x) +1 = 2tanx/(1 - tan2x) + 1 = 2tanx/(1 - tan2x) + (1 - tan2x)/(1 - tan2x) = (-tan2x + 2tanx + 1)/(1 - tan2x)

The same as the period of y = sin x. This period is equal to (2 x pi).

the period is 2pi. period is 2pi/b and the formula is y=AsinBx.

pi radians.

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It depends on the domain of x.

tan(2x) = 2tanx/(1 - tan2x) So tan(2x) +1 = 2tanx/(1 - tan2x) + 1 = 2tanx/(1 - tan2x) + (1 - tan2x)/(1 - tan2x) = (-tan2x + 2tanx + 1)/(1 - tan2x)

The same as the period of y = sin x. This period is equal to (2 x pi).

The period is 2*pi radians.

the period is 2pi. period is 2pi/b and the formula is y=AsinBx.

The period is the length of x over which the equation repeats itself. In this case, y=sin x delivers y=0 at x=0 at a gradient of 1. y next equals 0 when x equals pi, but at this point the gradient is minus 1. y next equals 0 when x equals 2pi, and at this point the gradient is 1 again. Therefore the period of y=sinx is 2pi.

pi radians.

2 pi

2

Pi

It is 2*pi radians.

pi/2