For a square of side a, the area is simple: a2. The perimeter is 4a. How do you deal with a circle, of diameter a? It's obviously less than a2. It turns out to be pi/4 times a2. Or pi times radius squared where pi has been worked out to be 3.1415..... As for angle, for lots of applications it appears a good way of measuring angle by using the length of a piece of circumference of a circle divided by the radius. The units for this is radians. A length of circumference equal to the circle radius gives an angle of 1 in these units when you draw straight lines from the ends of this bit of circumference to the centre. So the whole way around the circle (360o) then is 2.pi.r divided br r, radians, which is just 2 pi radians.
Area of a sector of a circle = (pi) x (radius)2 x (central angle of the sector / 360)
The area of the whole circle is pi*r2 = 25*pi To go any further, you need to assume that the central angle is given in degrees. If the sector is 18.0 degrees out of a circle of 360 degrees so the sector represents 18/360 = 1/20 of the whole circle. The area of the sector, therefore, is 1/20 of the area of the whole circle = 25*pi/20 = 5*pi/4 or 1.25*pi = 12.566 sq inches.
measure of central angle/360 degrees = area of sector/area of circle 110 degrees/360 degrees = 40 unit2/ pi r2 unit2 11/36 = 40/pi r2 11 pi r2 = 40 x 36 11 pi r2 = 1,440 r2 = 1,440/11 pi r = square root of 1,440/11 pi r = 20.3 unit approximately
Divide the angle measured in degrees by (180/pi). Alternatively, multiply by (pi/180).
The formula for the surface area of an elbow (or 90° angle) is (pi^2 * (radius2^2 - radius1^2) ) / 4. Where pi = 3.14159, radius 2 = the radius from the center to the outside, and radius 1 = the radius from the center to the inside.
the area of a sector = (angle)/360 x PI x radius x radius pi r squared
The hypotenuse is the longest side of a right angle triangle The area of a circle is pi*radius2
Area of whole circle = pi*r2 = 64*pi Area of Sector = Area of Whole Circle * Angle of Sector/Angle of Whole Circle = Area of Whole Circle * 120/360 = Area of Whole Circle / 3 = 64*pi/3 = 67.0 to the nearest tenth.
Acute angle in the range (0, pi/2) radians = (0, 90) degrees.Right angle = pi/2 radians = 90 degrees.Obtuse angle in the range (pi/2, pi) radians = (90, 180) degrees.Straight angle = pi radians = 180 degrees.Reflex angle in the range (pi, 2*pi) radians = (180, 360) degrees.Full turn = 2*pi radians = 360 degrees.
The area of the whole circle is PI x 6 squared which equals 36 PI. We can now use the ratio 30/36 = x/360 to find the angle (360 is the full angle if the circle, x is the angle of the segment, pi's cancell out) If we solve for x we get 300 degrees which is the angle we need. As for the length, the circles circumference is 12 PI (12 is the diameter). This means that 30/36= AB/12PI AB=10PI
The area is 0.5*pi*r2 where r is the radius. The angle is totally irrelevant since it will always by 180 degrees for a semicircle!
(pi * radius squared) * ( sector angle / 360 )
Multiply ( pi R2 ) by [ (angle included in the sector) / 360 ].
Area = r2*A where A is the angle measure in radians. = 8*8*80*pi/180 = 89.361 square units.
Area of a sector of a circle = (pi) x (radius)2 x (central angle of the sector / 360)
The area of the whole circle is pi*r2 = 25*pi To go any further, you need to assume that the central angle is given in degrees. If the sector is 18.0 degrees out of a circle of 360 degrees so the sector represents 18/360 = 1/20 of the whole circle. The area of the sector, therefore, is 1/20 of the area of the whole circle = 25*pi/20 = 5*pi/4 or 1.25*pi = 12.566 sq inches.
measure of central angle/360 degrees = area of sector/area of circle 110 degrees/360 degrees = 40 unit2/ pi r2 unit2 11/36 = 40/pi r2 11 pi r2 = 40 x 36 11 pi r2 = 1,440 r2 = 1,440/11 pi r = square root of 1,440/11 pi r = 20.3 unit approximately