2x - 13x + 42 = x +ax + b a + b = 2(x - 6.5x + 21) = 34 = a + b
x2 + 13x + 40 = x2 + 5x + 8x + 40 = x(x + 5) + 8(x + 5) = (x + 8)(x + 5)
x2 + x2 = 2x2
X^2 - 13X + 30 = 0 (X-3)(X-10) easy inspection problem
8
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
x2 + 13x + 36 = (x + 9)(x + 4)
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
(x-4)
(x + 4)(x + 9)
42 + x2 = 13x ∴ x2 - 13x + 42 = 0 ∴ (x - 6)(x - 7) = 0 ∴ x ∈ {6, 7}
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
572 Because 2x11=22 and 13x2=26 and 22x26=572.
x2 + 13x + 12 = (x + 1)(x + 12)
2x - 13x + 42 = x +ax + b a + b = 2(x - 6.5x + 21) = 34 = a + b
if x2 + 7 = 37, then x2 = 29 and x = ±√29
(x -3)(2x2 + 3x - 4)