11+2 = 13 and 2*11 = 22
So: x2+13x+22 = (x+2)(x+11) when factored
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x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
572 Because 2x11=22 and 13x2=26 and 22x26=572.
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
42 + x2 = 13x ∴ x2 - 13x + 42 = 0 ∴ (x - 6)(x - 7) = 0 ∴ x ∈ {6, 7}